Athermocouple, with a spherical junction diameterof 0.5 mm, is used for measuring the temperature of hot airflow in a circular duct. the convection heat transfer coefficient of the air flow can be related with the diameter (d) ofthe spherical junction and the average air flow velocity (v)as h 5 2.2(v/d)0.5, where d, h, and v are in m, w/m2? kand m/s, respectively. the properties of the thermocouple junction are k 5 35 w/m? k, r 5 8500 kg/m3, and cp 5320 j/kg? k. determine the minimum air flow velocity thatthe thermocouple can be used, if the maximum responsetime of the thermocouple to register 99 percent of the initial temperature difference is 5 s.

I’m good with pshycology

Answer would be

To compare speeds speeds of wagons we will use second newton's law. it states: f = m * ahere we can see that force depends on the acceleration. if we know acceleration for both wagons we can compare them to make conclusion of speeds of wagons.we have: m1 = 10lbm2 = 20lbf1 = 2*f2also: m2 = 2*m1for bill we have equation: f1 = m1 * a1for tom we have equation: f2 = m2 * a2after inserting identities we have: 2*f2 =m1 * a1f2 = 2*m1 * a2in order to make conclusions about speeds we will solve these equations for a and find their ratio: a1 = 2f2 / m1a2 = f2 / 2m1a1 / a2 = (2f2/m1) / (f2/2m1)a1 / a2 = (2f2*2m1) / (m1*f2)a1 / a2 = (4f2m1) / (m1f2)a1 / a2 = 4this ratio is bigger than 1 and this means that a1 is greater than a2. a1 is 4 times greater than a2. speed of bill's wagon is 4 times greater than speed of tom's wagon.

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