Aspace ship zips past mars’ orbit at a speed of 3 x 103 m/s and constantly accelerates in a straight line until it reaches the orbital path of jupiter, 5.56 x 1011 m away, when its speed is 4 x 104 m/s. find a) the space ship’s acceleration and b) the time required to travel from mars’ to jupiter’s orbits. (answer in days

Explanation:

given,

space ship speed = 3 x 10³ m/s

distance travel in straight line = 5.56 x 10¹¹ m

speed at that point = 4 x 10⁴ m/s

a) acceleration

          v² - u² = 2 a s

          (4 x 10⁴)² - (3 x 10³)² = 2 x a x 5.56 x 10¹¹

               a = 1.43 x 10⁻³ m/s²

b) time require to travel mars

        v + u  = a t

        4 x 10⁴ + 3 x 10³  = (1.43 x 10⁻³) t

        t = 30069930 sec

        t = 348 days