Resources: eoc v slo
sat/act/workkeys
ap/accuplacer y other
julsprcp
pour classroom partner
me assignments
assignment waves test review
les
the beam of a light spreads out after leaving the flashlight. the beam grows wider and wider. this is best explained by
a)
diffraction
b)
interference
c)
reflection
eliminate
dy
r efraction
submit
waves

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

The force is push or pull

D. the index of refraction of the second medium is lower.