Acurrent of 16.0 ma is maintained in a single circular loop of 1.90 m circumference. a magnetic field of 0.790 t is directed parallel to the plane of the loop.(a) calculate the magnetic moment of the loop. ma · m2(b) what is the magnitude of the torque exerted by the magnetic field on the loop? mn · m

Answer

given,

current (I) = 16 mA

circumference of the circular loop (S)= 1.90 m

Magnetic field (B)= 0.790 T

S = 2 π r

1.9 = 2 π r

r = 0.3024 m

a) magnetic moment of loop

    M= I A

    M=

   M=

   M=

b)  torque exerted in the loop

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explanation:

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