Acharged particle ( m = 5.0 g, q = −70 μc) moves horizontally at a constant speed of 30 km/s in a region where the free fall gravitational acceleration is 9.8 m/s 2 downward, the electric field is 700 n/c upward, and the magnetic field is perpendicular to the velocity of the particle. what is the magnitude of the magnetic field in this region?

B=0.047mT

Explanation:

The magnetic field in this region is given by the followin equation

Where

Replacing all of this values,

m = 5.0 g, q = −70 μC, g= 9.8 m/s^2, E=700N/C

We have,

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