Two long parallel wires separated by 5.0 mm each carry a current of 60 a. these two currents are oppositely directed. what is the magnitude of the magnetic field at a point that is between the two wires and 2.0 mm from one of the two wires?

B = 0.002 T

Explanation:

It is given that,

Distance between two parallel wires, d = 5 mm = 0.005

Current in each wire, I = 60 A

Let B is the magnitude of the magnetic field at a point that is between the two wires and 2.0 mm from one of the two wires. Firstly, calculating the magnetic field due to first wire is given by :

The magnetic field due to second wire is given by :

Let B is the net magnetic field from wire A, so,

B = 0.002 T

Hence, this is the required solution.

5 w for 1hr = 5x60x60 joules=300x60=3000x6=18,000j as total energy conversion. efficiency of bulb needed for radiant to thermal within 18000

higher potential

explanation:

because it is in a high speed so it must move into a of high potential