If the time from stimulus to response from the distal stimulating electrodes is 9.5ms and the time from stimulus to response from the proximal stimulating electrodes is 10.5ms and the distance between the two electrods is 55mm, what is the conduction velocity in m/s?

55m/s

Explanation:

conduction velocity (meter/second) is of a nerve is calculated by measuring the distance (millimeters) between two stimulation sites and dividing by the difference in latency (milliseconds) from the proximal.

mathematically is given as:

Conduction Velocity (meters/second) ={Distance (millimeters)}/{Proximal Latency- Distal Latency (millisecond)

C.V= (55mm)/ (10.5-9.5)ms

     =55m/s

The correct answer is 55m / s

Explanation:

Hello!

Let's solve this!

The formula for calculating speed is:

v = (x2-x1) / (t2-t1)

The data we have are:

x2 = 55mm * (1m / 1000mm) = 0.055

x1 = 0m

t2 = 10.5ms * (1s / 1000ms) = 0.0105s

t1 = 9.5ms * (1s / 1000ms) = 0.0095s

v = (0.055m) / (0.0105s-0.0095s) = 55m / s

The correct answer is 55m / s

f=ma newton

f=100x2.5=250n

the rearrangement of particles in a physical change. hope this