The enthalpy of fusion of mercury is 2.292 kj mol-1 at its normal freezing point of 234.3 k; the change in molar volume on melting is +0.517 cm3 mol-1. at what temperature will the bottom of a column of mercury (mass density 13.6 g cm-3) of height 10 m be expected freeze? the pressure at a depth d in a fluid with mass density rho is rhogd, where g is the acceleration of free fall, 9.81 ms-2.

T_2= 234.37 K

Explanation:

According to Claperyon, we know that

P_1= Atmospheric pressure 760 mm Hg

P_2 = pressure at the bottom of the column

= 10×10^3 mm of Hg+ 760 mm of Hg

= 10760 mm of Hg

now,

P_2-P_1= 10760-760= 10^4 mm

P_2-P_1 ( in pascals) = 10^4× 133.322= 1333220 mm

the enthalpy of fusion (ΔH-fus) of mercury is 2.292 KJ/mol

use the above equation to calculate ΔT as follows

therefore, T_2= 234.37 K

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the answer is a. at the equator