Calculate the root mean square velocity of nitrogen molecules at 25°c.

515.22 m/s

Explanation:

Formula for root mean square velocity is SQRT (3RT/M)

Where,

R = Rydberg's constant = 8.314 Kg. m²/ s². K. mol

T = Temperature in Kelvin

M = Molar mass in Kg/mol

First calculate molar mass,

As nitrogen is diatomic molecule,

Its molar mass is

M = 2(14) = 28 g/mol

Convert unit into Kg/mol

28 g/mol x 1 Kg/1000g = 2.8x10¯² Kg/mol

Convert temperature into kelvin

T = 25 + 273 = 298K

Put all values in formula

Vrms = SQRT (3RT/M)

Vrms = SQRT (3x8.314x298/2.8x10¯²)

Vrms = SQRT (265454. 14)

Vrms = 515.22 m/s

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2

momentum of soft ball three times less than baskey ball