An archer fish launches a droplet of water from the surface of a small lake at an angle of 70° above the horizontal. he is aiming at a juicy spider sitting on a leaf 40 cm to the east and on a branch 23 cm above the water surface. the fish is trying to knock the spider into the water so that the fish can eat the spider. (a) what must the speed of the water droplet be for the the fish to be successful?

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j