Aresistor is made out of a long wire having a length l. each end of the wire is attached to a terminal of a battery providing a constant voltage v0. a current i flows through the wire. if the wire were cut in half, making two wires of length l/2, and both wires were attached to the battery (the end of both wires attached to one terminal, and the other ends attached to the other terminal), what would be the total current flowing through the two wires?

The current is 4 times the current of the full length wire.

Explanation:

The resistor value is directly proportional to its length:

the current is given by:

so if the wire was cut in the half:

Both ends of the wire were connected to the battery, so they are connected in parallel, the equivalent resistor is given by:

So the current is:

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm.   the wire diameter is d = 0.9 mm.   the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a                                          

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2)   in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation:

do you have a formula possibly