Iam confused on how to do either of these problems.

19. a) 48.3 m

     b) 88.2 m

20. a) t ≅ 6.38 s

      b) ≅270.1 m

Explanation:

Use basic linear motion equations for each of these questions, correctly.

s = ut + a

a) applying the equation to the horizontal direction,

s = ut = 11.5×4.2 = 48.3 m ( as gravitational acceleration for horizontal direction is zero)

b) applying the equation to the vertical direction in downward direction,

     s = h( height ) =0 + g ( as initial velocity in vertical direction is zero.)

           h = 0.5×10×

              =88.2 m

20) Using the same equation,

a)  s = ut + a apply it for vertical motion just as it reachs the ground in upwards direction,

0 = usin37°t - g

53(0.6081) = 0.5×10×t

t ≅ 6.38 s

b) again same equation in horizontal direction,

s = ucos37°t = 53×0.7986×6.38

  ≅270.1 m

an ion is a charged atom or molecule. it is charged because the number of electrons do not equal the number of protons in the atom or molecule. an atom can acquire a positive charge or a negative charge depending on whether the number of electrons in an atom is greater or less then the number of protons in the atom.

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s