Ametal block of density 9000kgcm3 weighs 70n in air. find its weight when it is immersed in paraffin wax of density 800kgm3? (take g=10ms-2)

Note: the text says that the density of the block is (not , which not a plausible value)

63.9 N

Explanation:

We want to find the apparent weight of the block when it is in water.

First of all, we know its true weight:

W = 70 N

So we can find the mass of the block:

where is the acceleration of gravity.

From the mass and the density, which is

we find the volume of the block:

We know that when the block is immersed in paraffin, it is acted upon the buoyant force, which acts upward, and whose magnitude is

where

is the density of paraffin

V is the volume of paraffin displaced, which corresponds to the volume of the block

Substituting,

Therefore, the apparent weight of the block in paraffin will be:

63.788 N

Explanation:

Density of a metal block  =  9000 ×〖10〗^(-6)  kgm^(-3)

Mass of the metal block = 70/10 = 7 kg

Volume = Mass/ Density

Volume of the metal block = 7/9000 ×(10)^(-6)  kgm^(-3)

      = 777.777 m^3

When it’s immersed in water up thrust is acted on a metal block then the weight is reduced due to up thrust, Let’s take W as a New measurement,

W + U = 70

W = 70-U

W = 70 -Vρ_l g

W= 70 – 777.77×800×(10)^(-6)×10

W = 63.778 N

answer; equivalent to a one(1) horsepower motor;

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .