Aone-piece cylinder has a core section protruding from the larger drum and is free to rotate around its central axis. a rope wrapped around the drum of radius 1.33 m exerts a force of 4.35 n to the right on the cylinder. a rope wrapped around the core of radius 0.51 m exerts a force of 6.62 n downward on the cylinder. what is the magnitude of the net torque acting on the cylinder about the rotation axis? answer in units of n m

Magnitude the net torque about its axis of rotation is 2.41 Nm

Solution:

As per the question:

The radius of the wrapped rope around the drum, r = 1.33 m

Force applied to the right side of the drum, F = 4.35 N

The radius of the rope wrapped around the core, r' = 0.51 m

Force on the cylinder in the downward direction, F' = 6.62 N

Now, the magnitude of the net torque is given by:

where

= Torque due to Force, F

= Torque due to Force, F'

Now,

The net torque comes out to be negative, this shows that rotation of cylinder is in the clockwise direction from its stationary position.

Now, the magnitude of the net torque:

i need to show me the graph so i can give u an answer

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