Will give brainliest, 30 points! : )
on the apollo 14 mission to the moon, astronaut alan shepard hit a golf ball with a golf club improvised from a tool. the free-fall acceleration on the moon is 1/6 of its value on earth. suppose he hit the ball with a speed of 35 m/s at an angle 28 ∘ above the horizontal.

a) how long was the ball in flight?

b) how far did it travel?

c) ignoring air resistance, how much farther would it travel on the moon than on earth?

a) 20.2 s

To find the time of flight of the ball, we just need to study its vertical motion.

The vertical motion of the ball is a uniform accelerated motion (free-fall), so we can use the suvat equation

(1)

to find the time it takes for the ball to reach the maximum height. Here we have:

at the instant when the ball reaches the maximum height

is the acceleration of gravity on the Mooon

is the initial vertical velocity of the ball, where

u = 35 m/s is the initial speed

is the angle of projection

Substituting,

And now we can solve (1) to find the time the ball takes to reach the maximum height:

And since the motion downward is symmetrical, the total time of flight is just twice this time:

b) 624.2 m

The horizontal distance travelled by the ball is completely determined by the horizontal motion, which is a uniform motion at constant speed.

The horizontal velocity of the ball is

And it is constant during the entire motion, as there are no forces acting along this direction.

Therefore, the horizontal distance travelled is given by:

And substituting the time of flight,

t = 20.2 s

We find

c) 521 m

In this case, we have to re-do the exercise on the Earth, where the acceleration due to gravity is

The initial velocities along the horizontal and vertical direction are the same, so the time taken for the ball to reach the maximum height is:

And so the time of flight is

Therefore, the horizontal distance travelled is

And so, the difference between the distance travelled by the ball on the moon and on the Earth is

it's a b and