The loop is in a magnetic field 0.20 t whose direction is perpendicular to the plane of the loop. at t = 0, the loop has area a = 0.285 square m. suppose the radius of the elastic loop increases at a constant rate, dr/dt = 3.70 cm/s .a) determine the emf induced in the loop at t = 0.b)determine the emf induced in the loop at t = 1.00 s .

Answer

given,

magnetic field = 0.20 T

at t = 0

area of loop = 0.285 m²

dr/dt = 3.70 cm/s

r = 0.301

emf at t = 0

E = 14 mV

at t = 1 radius of loop

r = 0.301 + 0.037 x 1

r = 0.338 m

emf at t = 1

E =15.71 mV

mistakes are ok

note: the given question is incomplete.

complete question is given below.

which is an example of kinetic energy?

a. the energy stored in ethanol  

b. a hockey puck sliding across the ice  

c. a compressed spring  

d. a ball sitting at the top of a ramp

solution: the kinetic energy is the energy posses by the virtue of the motion of the object.

in the given options, a, c and d are the example of potential energy because it is the energy posses by the virtue of the rest of the object. but option b has the kinetic energy as the object is in motion.

hence, a hockey puck sliding across the ice   is the apex example of kinetic energy.

so, the option (b) a hockey puck sliding across the ice   is the correct option.