As the driver steps on the gas pedal, a car of mass 1 140 kg accelerates from rest. during the first few seconds of motion, the car's acceleration increases with time according to the expression below, where t is in seconds and a is in m/s2. a = 1.14 t - 0.210 t2 + 0.240 t3 (a) what is the change in kinetic energy of the car during the interval from t = 0 to t = 2.60 s? j (b) what is the minimum average power output of the engine over this time interval? w (c) why is the value in part (b) described as the minimum value?

(a)

(b) P = 6309.6981 W

(c) Value in above part is described as minimum because there would have been power loss in the actual system to achieve this acceleration from the state of rest.

Explanation:

Given:

mass of car, m = 1140 kg

expression of acceleration,

where "t" is time in seconds

initial time,

final time,

(a)

We know,

Kinetic Energy

∴

(b)

We know,

Power

P = 6309.6981 W

(c)

Value in above part is described as minimum because there would have been power loss in the actual system to achieve this acceleration from the state of rest.

d) physical means can be used to separate the components of air.

the duration of a photographic flash is related to an rc time constant, which is 0.100 μs for a certain camera.