Phoebe threw a frisbee horizontally that traveled 125 m. the frisbee left her hand traveling at 45 m/s. as the frisbee travels in the air it slows down with a deceleration of 5.6 m/s2. how long was the frisbee in the air? when mike caught it, how fast was it traveling?

1) 3.57 s

The motion of the frisbee is a uniformly accelerated motion, so we can use the suvat equation:

where

s is the displacement

u is the intiial velocity

t is the time

a is the acceleration

Here we have

s = 125 m (distance travelled)

u = 45 m/s (initial velocity)

(deceleration of the frisbee)

Substituting into the equation, we get

The solution of this equation are:

Which gives two solutions:

t = 3.57 s

t = 12.50 s

So, the frisbee crosses the point at distance d = 125 m from Phoebe two times: at 3.57 s the first time, then if it is free to move, the frisbee continues its motion and then at some point moves back to this point at t = 12.5 s. Since we are interested in the time at which Mike caught the frisbee, we just take the first solution:

t = 3.57 s

2) 25 m/s

Since this is a uniformly accelerated motion, the velocity of the frisbee is given by

where we have

u = 45 m/s is the initial velocity

is the acceleration of the frisbee

Since the frisbee has been caught at time

t = 3.57 s

We can substitute this value into the equation to find the final velocity of the frisbee:

The frisbee was in air for 12.5 seconds and when mike caught it it's speed was = 10m/s

Explanation:

we know that distance travelled horizontally is given by  

where s = total distance travelled = 125 (given),

u = initial velocity = 45m/s (given) ,  

a = acceleration = -5.6 (since we are given deceleration a = negative) and

t = total travel time

substituting these values in the formula  

125 = 45*t + (1/2)(-5.6)

we get t = 12.5 and 3.578... since 12.5 is more accurate value

we take t = 12.5 which gives the time for which frisbee stays in air

also we know speed =

since we are given total distance = 125m  

and total time we have found, t = 12.5

we get speed =

                       = 10m/s is how fast the frisbee was when mike caught it.

where is the circuit diagram ?

distance = 150m

displ = root (50 ^2 + 100^2)

root(2500+10000)

root 125000