Asuspension bridge with weight uniformly distributed along its length has twin towers that extend 90 meters above the road surface and are 800 meters apart. the cables are parabolic in shape and are suspended from the tops of the towers. the cables touch the road surface at the center of the bridge. find the height of the cables at a point 200 meters from the center. (assume that the road is level.) the height of the cables is nothing meters.

y=22.5 m

Explanation:

Given that

P (800 , 90)

Shape is parabolic

When x= 200 m we have to find the values of y

We know that equation of parabola

y = a x²

At x= 400 m y= 90 m   ( 400 distance from center)

So

90 = 400² a     ( 400 distance from center)

a=90/400² = 90/(160000)

y = a x²

y = 90/(160000) x²

When x= 200 m

y = (90 x  200² )/(160000)

y= 90 x 40000/(160000)

y= 90 x 4/(16)

y=22.5 m

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day