Acircular saw blade with radius 0.175 m starts from rest and turns in a vertical plane with a constant angular acceleration of 2.00 rev/s^2. after the blade has turned through 155 rev, a small piece of the blade breaks loose from the top of the blade. after the piece breaks loose, it travels with a velocity that is initially horizontal and equal to the tangential velocity of the rim of the blade. the piece travels a vertical distance of 0.820 m to the floor.

(a) how far does the piece travel horizontally, from where it broke off the blade until it strikes the floor? express your answer with the appropriate units.

l = ?

The distance the piece travel in horizontally axis is

L=3.55m

Explanation:

Now the angular velocity is the blade speed so:

assuming no air friction effects affect blade piece:

time for blade piece to fall to floor

Now is the same time the piece travel horizontally

blade piece travels  HORIZONTALLY = (24.5)(0.397) = 9.73 m  ANS

i think its

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂