If one of the masses of the atwood's machine below is 2.9 kg, what should be the other mass so that the displacement of either mass during the first second following release is 0.28 m? assume a massless, frictionless pulley and a massless string. (there are two possible answers for m2. enter your answers from smallest to largest.)

2.59 Kg, 3.25 Kg

Explanation:

Acceleration can be found using equation

where s is the release distance, a is acceleration and t is time

Making a the subject of the formula

Substituting 0.28 for s and time for 1 second

Acceleration formula for the Atwood machine is given by

 where m1 and m2 are first and second masses respectively

Two situations are possible

When m1>m2

Assuming m1 is 3.7kg which is heavier than m2

Substituting a for  and m1 as 2.9Kg and taking acceleration due to gravity as  

10.37m2=28.449-1.624

10.37m2=26.825

m2=2.59 Kg

When m1<m2

Then m1=2.9Kg hence

-9.25m2=-28.449-1.624=-30.073

9.25m2=30.073

m2=3.25 Kg

when a device is used in a circuit in which the voltage is 81 v, the current flowing through the device is 3 a. what is the resistance of the device?

a. 27 ω

b. 40.5 a

c. 243 ω

d. 243 a

the correct answer is a. 27

the answer would most likely be c, because if it's a comical piece of information, it may likely not be true, if it's a site that allows anybody to edit the content, it could mean a five year old is typing the info, and if it's a tv show produced by a celeb, it may have a biased opinion.