In a certain experiment, cylindrical samples of diameter 4 cm and length 7 cm are used. the two thermocouples in each sample are placed 0.12 m apart. after initial transients, the electric heater is observed to draw 0.6 a at 110 v, and both differential thermometers read a temperature difference of 8°c. determine the thermal conductivity of the sample. the thermal conductivity of the sample is:

K = .3941 × 10³ W/m.K

Explanation:

Qcond = K A ΔT÷ L

∴K = Qcond ×L ÷ A ΔT

J ÷ S = P

P = I × V =Qcond

∴Qcond = I × V

               = 0.6 A × 110 V

               =66 W

L = 0.12 m

ΔT = 8 °C

Qcond =33 V

Area = (πD²) ÷ 4

       = [π (4 × 10⁻² )²] ÷  4

        = 1.256 × 10⁻³ m²

∴A = 1.256 × 10 ⁻³³ m²

So K = ( Qcond × L ) ÷ A ΔT

         = (33) (0.12 ) ÷ (1.256 ×10⁻³ ) × 8

         = 0.3941 × 10³ W/m .K

show the wavelengths of a wave. show the crests of a wave.

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.