Benzene is a carcinogenic (cancer-causing) compound. a benzene-contaminated water sample contains 5.9×10−5 % benzene by mass. part a what volume of the water in liters contains 235 mg of benzene? (assume that the density of the solution is 1.0 g/ml.)

398.3 L

Explanation:

Percent composition is percentage by the mass of element present in the compound.

Given that the benzene is % by mass.

It means that of benzene is present in 100 g of the total sample

Also, Given that : Mass of benzene = 235 mg = 0.235 g ( 1 mg = 0.001 g)

Mass % =

Thus,

Mass of the sample = = 398305.08474 g

Mass of benzene = 0.235 g

Thus, Mass of water = 398304.85 g

Density = 1 g/mL

So, Volume = 398304.85 mL = 398.3 L ( 1 mL = 0.001 L)

you have to draw the persons position over there

= initial pressure

= final pressure = 2

= initial volume

= final volume = /4

= initial temperature = 20 c = 20 + 273 = 293 k

= final temperature = ?

using the equation