Let f(v) be the gas consumption in liters/km of a car traveling at velocity v km/hr. in addition, you know that f(60) = 0.05 and f '(60) = 0.0005 . (a) let g(v) be the distance in km that the car goes on one liter of gas at velocity v. what is the relationship between g(v) and f(v) ?

15.3 cos 65 degrees trig

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft

elctricity and magnet is conversion to it