Auniform, solid disk with mass m and radius r is pivoted about a horizontal axis through its center. a small object of the same mass m is glued to the rim of the disk. if the disk is released from rest with small object at the end of a horizontal radius, find the angular speed when the small object is directly below the axis.

Explanation:

According to the law of the conservation of energy, the gravitational potential energy of the physical system will be converted into rotational kinetic energy. So, we have:

Is the moment of inertia of the system, that is the sum of the moments of inertia of the disk and the small object.

f=ma a/f/m a= 480/60 a = 8m/s/s that is quick wow