Ablock of aluminum at a temperature of t1 = 32 degrees c has a mass of m1 = 12 kg. it is brought into contact with another block of aluminum with a mass of m2 = 0.5m1, at a temperature of t2 = 9 degrees c. this aluminum has a heat capacity of c = 899 j/kg k.

Explanation:

Given

mass of First Block

Temperature

mass of second block

Temperature

Heat capacity of aluminium c=899 J/kg-K

Final Temperature acquired by both blocks at steady state

Heat loss first block =Heat gain by second block

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s