What is an object's final velocity if it has an initial velocity of +12
meters/second with a constant acceleration of +14
meters/second and has traveled 48 meters in the +x direction?

v = 38.57 m/s

Explanation:

Given that,

The initial velocity of the object in x direction, u = 12 m/s

The acceleration of the object in x direction, a = 14 m/s²

The distance traveled by the object in x direction, s = 48 m

The equations of motion of a moving body with initial velocity and acceleration is given by the formula

                                      v² = u² + 2as

Substituting the values in the above equation

                                      v² = (12 m/s)² + 2 x 14 m/s² x 48 m

                                           = 1488

Therefore,                      

                                        v = 38.57 m/s

Hence, the final velocity of the body, v = 38.57 m/s

in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.

answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

according to question, we have said that if the population has twice its initial population, then it becomes

so, time taken to reach this above mentioned population is given by

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.