above Earth's surface
is the Earth's mass
![\frac{(2\pi)^2 r^2}{T^2}=\frac{GM}{r}\\r=\sqrt[3]{\frac{GMT^2}{(2\pi)^2}}=\sqrt[3]{\frac{(6.67\cdot 10^{-11})(5.98\cdot 10^{24})(7740)^2}{(2\pi)^2}}=8.46\cdot 10^6 m](/tpl/images/0350/1161/16faf.png)
is the radius of the satellite's orbit
An artificial satellite circling the earth completes each orbit in 129 min
(a) find the altitud...
Physics, 28.10.2019 23:31, kaoris6368
An artificial satellite circling the earth completes each orbit in 129 min
(a) find the altitude of the satellite.
(b) what is the value of g at the location of this satellite?
Answers: 2
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