Aconductor carrying 14.7 amps of current is directed along the positive x-axis and perpendicular to a uniform magnetic field. a magnetic force per unit length of 0.125 n/m acts on the conductor in the negative y direction. what is the strength of the magnetic field at the place where the current is?

0.0085 T

Explanation:

The magnetic force per unit length exerted on a current-carrying wire is given by

where

B is the strength of the magnetic field

I is the current

is the angle between the directions of B and I

In this problem, we know

I = 14.7 A (the current)

since I and B are perpendicular

Therefore, solving for B, we find the strength of the field:

it has to be b, about 97 percent.