Two cars collide inelastically and stick together after the collision. before the collision, the magnitudes of their momenta are p1 and p2 . after the collision, what is the magnitude of their combined momentum? a) p1+p2b) p1-p2c) p2-p1d)(p1p2)^(1/2)e) (1/2)(p1+p2)f)(p1+p2)^(1/2)g)the answer depends on the directions in which the cars were moving before the collision.

The correct answers are A, B, C

Explanation:

In the problems of the moment, the most important thing is to define those who form the system so that the forces during the crash have been internal, the moment can be conserved. In this case the system is made up of the two cars. We write the equations just before and after the crash

Before the crash

     p₀ = P1 + P2

After the crash

     pf = (m1 + m2) v

    p₀ = pf

   P1 + P2 = (m1 + m2) v = Pf

Let's analyze the possible initial diversions of cars

-Car 1 travels to the right

      Car 2 to the right

           Pf = P1 + P2

      Car2 to the left

           Pf = P1-P2

-Car 1 to the left

       Car 2 to the right

            Pf = -P1 + P2

      Car 2 to the left

           Pf = -P1 -P2

The correct answers are A, B, C

explanation:

v=uf/(u-f)

= 5.-10/(5+10) convex lens has negative focal length

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2