Asatellite orbits earth. the only force on the satellite is the gravitational force exerted by earth. how does the satellite’s acceleration compared to the gravitational field at the location of the satellite?

Given that , then is considerably greater than , which tends to be zero. ().

Let be and the masses of the satellite and the Earth, respectively. By the Newton's Law of Gravitation, the accelerations experimented by the satellite and the Earth (, ), in meters per square second, are, respectively:

Satellite

(1)

Earth

(2)

Where:

If we know that , then is considerably greater than , which tends to be zero. ().

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here we can say that acceleration of the satellite is same as the gravitational field due to Earth at that location

Explanation:

As we know that gravitational field is defined as the force experienced by the satellite per unit of mass

so we will have

now in order to find the acceleration of the satellite we know by Newton's II law

so we will have

so here we can say that acceleration of the satellite is same as the gravitational field due to Earth at that location

speed

ratio of distance traveled to time interval

net force

vector sum of forces on object

object

source of diverging light rays either luminous or illuminated

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explanation:

temp rises, and expansion