A81 kg man is riding on a 40 kg cart traveling at a speed of 2.3 m/s. he jumps off with zero horizontal speed relative to the ground. what is the resulting change in the cart's speed, including sign?

Explanation:

In this case we have to use the Principle of conservation of Momentum:

This principle says that in a system  the total momentum is constant if no external forces act in the system. The formula is:

Where:

Mass of the first object.

Mass of the second object.

Initial velocity of the first object.

Initial velocity of the second object.

Final velocity of the first object.

Final velocity of the second object.

In this problem we have:

Observation: Is because the system has the same initial velocity.

First we have to find ,

We can rewrite it as:

Replacing with the data:

We found the final velocity of the cart, but the problem asks for the resulting change in the cart speed, this means:

Then, the resulting change in the cart speed is:

beta is electron from nucleus

something from nucleus has changed, but charge must be same for cons of charge

answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg