Two skaters, one with mass 65 kg and the other with mass 35 kg, stand on an ice rink holding a rope of length 15 m and negligible mass. starting from the ends of the rope, the skaters pull themselves along the rope until they meet. how far does the 35 kg skater move? ignore friction.

the two skaters will meet at a distance of 9.75 m from the initial position of 35 kg skater

Explanation:

Since there is no external force on the system of two skaters

So the two skaters will meet at the position of their center of mass

so let the position of 35 kg skater is origin

then the position of other skater is 15 m

now by the formula of center of mass we have

so the two skaters will meet at a distance of 9.75 m from the initial position of 35 kg skater

0.3x0.21x0.08kg=mass 1 sheet

mass 500 = 500xmass 1

volume pile = 0.3x0.2x0.048

density=mass/volume= 500xmass 1/0.3x0.2x0.048

v patient student

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .