Aprojectile (mass = 0.15 kg) is fired at and embeds itself in a stationary target (mass = 2.44 kg). with what percentage of the projectile's incident kinetic energy does the target (with the projectile in it) fly off after being struck?

38.6 %

Explanation:

First of all, we have to calculate the final velocity of the block-bullet system. We can apply the law of conservation of momentum:

where

m = 0.15 kg is the mass of the bullet

u is the initial velocity of the bullet

M = 2.44 kg is the mass of the block

U = 0 is the initial velocity of the block (it is at rest)

v is the final velocity of the bullet+block

Solving for v,

The total initial kinetic energy of the system is just the kinetic energy of the bullet:

While the final kinetic energy of the block+bullet is:

So the fraction of kinetic energy lost is

And so, the fraction of kinetic energy left in the projectile after he flies off the block is

1 - 0.614 = 0.386 = 38.6 %

  the unit of the measure =

explanation:

  the property that is quantified by the energy needed per of material to raise the temperature by one.

  si unit of energy = joule (j)

  si unit of temperature = kelvin (k)

  si unit of mass of material = kilogram (kg)

the property that is quantified by the energy needed per of material to raise the temperature by one is called specific heat.

the unit of specific heat is

root word, prefixes, and suffixes