To understand the vector nature of momentum in the case in which two objects collide and stick together. in this problem we will consider a collision of two moving objects such that after the collision, the objects stick together and travel off as a single unit. the collision is therefore completely inelastic. you have probably learned that "momentum is conserved" in an inelastic collision. but how does this fact you to solve collision problems? the following questions should you to clarify the meaning and implications of the statement "momentum is conserved."

What formula  this one  (x_/

To a fellow spongebob-ian i will be glad to , the cheetah didn't get far on purpose because he's a cheetah  ( ͡° ͜ʖ ͡°)

Answer: a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same sign as the  -4.0  µc charge.======electricstatic force between two point charges  is given by    where k is coulomb's constant,  8.99×10⁹  n·m²/c², q₁ and q₂ are the point charges, and r is the distance between the two point charges.assign positive to q₁let q₁ =  6.0 µc, q₂ = -4.0  µc, q₀ represent the charge at the origin, and q₃ represent this new charge to place.the charge at the origin q₀ would experience the following force f₀₁ from q₁, with r = 6.0 m (note that 1  µc = 10⁻⁶ c)    the force from q₂    the force from q₃    the net force on the origin charge, q₀, has to be zero for no electrostatic forcehaving an equation where k and q₀ can be divided out of the equation will allow us to solve for q₃    isolating:     a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same as the  -4.0  µc charge