Tarzan swings on a 26.2 m long vine initially inclined at an angle of 28° from the vertical. (a) what is his speed at the bottom of the swing if he starts from rest? m/s (b) what is his speed at the bottom of the swing if he starts with an initial speed of 3.00 m/s? m/s

Answer

given,

length of the swing = 26.2 m

inclined at an angle = 28°

let, the initial height of the Tarzan be h

h = L (1 - cos θ)

a) initial velocity v₁ = 0 m/s

   final velocity of Tarzan = v_f

law of conservation of energy

  PE_i + KE_i = PE_f + KE_f

                          = 7.75 m/s

the speed tarzan at the bottom of the swing

v_f = 7.75 m/s

b)initial speed of the  = 3 m/s

                       v_f= 11.29 m/s

a and b sometimes have a positive value