Acrate rests on the flatbed of a truck that is initially traveling at 15 m/s on a level road. the driver applies the brakes and the truck is brought to a halt in a distance of 38 m. if the deceleration of the truck is constant, what is the minimum coefficient of friction between the crate and the truck that is required to keep the crate from sliding?

0.3

Explanation:

Given

velocity of car=15 m/s

truck brought to halt in a distance of 38 m

We know

Final velocity (v)=0

 (deceleration)

Therefore minimum coefficient of friction \mu will be

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards

the rearrangement of particles in a physical change. hope this