Applying a constant net force to an object causes it to accelerate at 10 m/s2. what will the acceleration of the object be if (a) the force is doubled, (b) the mass is halved, (c) the force is doubled and the mass is doubled, (d) the force is doubled and the mass is halved, (e) the force is halved, (f) the mass is doubled, (g) the force is halved and the mass is halved, and (h) the force is halved and the mass is doubled?

Explanation:

The force is directly proportional to mass and acceleration.

a) If force is doubled then acceleration is doubled.

b) If mass is halved then acceleration of the will increase if the force is constant.

c) If the force is doubled and the mass is doubled then acceleration is halved.

Dividing the equation

d) If the force is doubled and the mass is halved then acceleration is doubled

e) If the force is halved then the acceleration is halved.

f) If the mass is doubled then the acceleration is halved keeping the constant force

g) If the force is halved and the mass is halved then the acceleration is doubled

h) If the force is halved and the mass is doubled then the acceleration is halved.

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

molecules are free to separate from each other and will take on the shape of the container. molecules move completely at random and high speeds. they vibrate in a fixed position and do not move around much. molecules expand to the edge of their container.