Ahome run just clears a fence 105 m from home plate. the fence is 4.00 m higher than the height at which the batter struck the ball, and the ball left the bat at a 31.0° angle above the horizontal. at what speed did the ball leave the bat?

u= 35.30 s

Explanation:

given,

horizontal distance covered by the ball = 105 m

vertical distance to clear by the ball = 4 m

angle at which the ball was hit = 31°

Let the initial velocity is u m/s and the ball take t sec to reach the fence.

ut = 122.5

Using

t = 3.47 s

now,

u= 35.30 s

Speed of the ball when it leaves the bat u= 35.30 s

atomic = no of protons.

mass number-atomic number = neutron number

no. dot product   =0 when vecs at right angles