Astone is thrown horizontally with an initial speed of 9 m/s from the edge of a cliff. a stop watch measures the stone's trajectory time from the top of the cliff to the bottom to be 4.7 s. what is the height of the cliff? round to the nearest tenth of a meter

the height of the cliff is equal to 108.241 m

Explanation:

given,

initial speed of the stone horizontally  = 9 m/s

vertical speed of the stone = 0 m/s

time taken of the trajectory = 4.7 s

using equation of motion

s = 108.241 m

hence, the height of the cliff is equal to 108.241 m

6/12=1/2

step-by-step explanation:

jupiter is the largest planet in our solar system, having a mass and radius that are respectively, 318 and 11.2 times that of earth. suppose that an object falls from rest near the surface of each planet and that the acceleration due to gravity remains constant during the fall. each object falls the same distance before striking the ground. determine the ratio of the time of fall on jupiter to that on earth.