An unspecified force causes a 0.20-kg object to accelerate at 0.40 m/s2. if 0.30 kg is added to the 0.20-kg object and the force remains the same, what is the acceleration (in m/s2) of the heavier object? (never include units with the answer to a numerical question.)

a = 0.16

Explanation:

given,

mass of the object 1 = 0.2 kg

mass of the object 2 = 0.3 kg

acceleration when force is on 0.2 kg = 0.4 m/s²

acceleration when both mass are combine = ?

F = m a

F = 0.2 × 0.4

F = 0.08 N

force acting is same and total mass  = 0.2 + 0.3 = 0.5 Kg

F = m a

a = 0.16 m/s²

the acceleration  acting when both the body is attached is a = 0.16

the current is 0.6

voltage ÷ resistance = current

so 12 ÷ 20 = 0.6

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer