Suppose that the magnitude of the force between two charged particles that are 2 cm apart is 50 n. what will the distance r between the particles be when the magnitude of the force between them is 200 n?

The distance between the particles have to be

x=0.01m or 1 cm

Explanation:

Using the law of Coulomb for two charge particles

Notice you don't know the value of K or q1 or q2 however the value is the same in both cases, so you don't need to know exactly the value of each one you can put constant in the equation like this:

C

Now to find r can use the value of K

The distance r between the particles will be 1 cm.

Electric charge consists of two types i.e. positively electric charge and negatively electric charge.

There was a famous scientist who investigated about this charges. His name is Coulomb and succeeded in formulating the force of attraction or repulsion between two charges i.e. :

F = electric force (N)

k = electric constant (N m² / C²)

q = electric charge (C)

r = distance between charges (m)

The value of k in a vacuum = 9 x 10⁹ (N m² / C²)

Let's tackle the problem now !

Given:

initial distance = d₁ = 2 cm

initial force = F₁ = 50 N

final force = F₂ = 200 N

Unknown:

final distance = d₂ = ?

Solution:

Grade: High School

Subject: Physics

Chapter: Static Electricity

Keywords: Series , Parallel , Measurement , Absolute , Error , Combination , Resistor , Resistance , Ohm , Charge , Small , Forces