Acomputer that is 87% efficient consumes 375 kwh of energy. how much useful energy does it provide?

326.25 kWh

Explanation:

Efficiency of a machine is defined as the ratio of useful energy to that of the energy consumed by the machine.

Here, efficiency is given as 87% and the energy consumed by the computer is 375 kWh.

Efficiency,

Plug in the values of and 375 kWh for energy consumed. Solve for useful energy. This gives,

Efficiency,

Therefore, the useful energy provided by the computer is 326.25 kWh.

b.

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