In the bohr model of the hydrogen atom, an electron moves in a circular path around a proton. the speed of the electron is approximately 2.20 x 10^6 m/s. find (a) the force acting on the electron as it revolves in a circular orbit of radius 0.530 x 10^-10 m and (b) the centripetal acceleration of the electron.

a) fc = m*v^2/ r
fc = 9.10938188*10^-31 * (2.2*10^6)^2 / (0.53*10^-10)
fc = 8.3188 *10^-8 n

b) ac = fc / m =
8.31876*10^-8 / (9.10938188*10^-31) = 9.1321*10^22 m/s^2

Explanation:

It is given that,

Radius of the circular orbit,  

Speed of the electron,

Mass of the electron,

(a) The force acting on the electron is centripetal force. Its formula is given by :

(b) The centripetal acceleration of the electron is given by :

Hence, this is the required solution.

the chart show the masses and velocities of two colliding objects that stick together after a collision.

according to the law of conservation of momentum, the momentum of the object after the collision is  

answer

1,500

kg • m/s.