Acoin slides over a frictionless plane and across an xy coordinate system from the origin to a point with xy coordinates (4.0 m, 5.8 m) while a constant force acts on it. the force has magnitude 1.3 n and is directed at a counterclockwise angle of 121° from the positive direction of the x axis. how much work is done by the force on the coin during the displacement?

i understand that w=fd and f=ma

w=1.3*d, but im not quite sure how exactly to find displacement.

Work done, W = 3.78 Joules

Explanation:

It is given that,

Displacement in x-y coordinate,

Magnitude of force, F = 1.3 N

The force is directed at a counterclockwise angle of 121° from the positive direction of the x axis. Let W is the work done by the force on the coin during the displacement.

Firstly, finding the vector form of force as :

The work done is given by :

W = 3.78 Joules

So, the work done by the force is 3.78 Joules. Hence, this is the required solution.

when earth is in rotational motion around the sun,it displaces from its place.

when a ball is placed on an inclined surface it does both the rotational and circular motion.

explanation:

if the person is shown to have +90n, then ans is -10n.

if the person is shown to have -90n, then ans is +10n.