Afireworks shell is accelerated from rest to a velocity of 50.0 m/s over a distance of 0.240 m. (a) how long (in s) did the acceleration last? s (b) calculate the acceleration in m/s^2). (enter the magnitude.) /s^2

0.0096 seconds

5208.33 m/s²

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

The acceleration of the firework shell was 5208.33 m/s²

The acceleration lasted for 0.0096 seconds

(a) 0.0096 sec

(b)

Explanation:

We have given that firewall shell starts from rest so initial velocity u = 0 m/sec

And final velocity v = 50 m/sec

Distance s = 0.240 m

(A) From first equation pf motion we know that v = u+at

So 50 = 0+at

at = 50

Now from second equation of motion

Using the value of at = 50

(b) As at = 50

So

c because the news are a source of information of things that happen on the daily and shows evidence about that particular topic

as we know our atmosphere or air have different levels. every level has other gasses, and every gas has another permeability. when the light comes from lower permeability to higher permeability, it changes its direction. so that means that when the light comes from the moon to the earth, it changes it's direction many more times. it basically means that the shape of the light part of the moon is changed on the earth.

hope this ! this is not copied! search it up, it's free of plagiarism!