Two waves on identical strings have frequencies in a ratio of 2 to 1. if their wave speeds are the same, then how do their wavelengths compare?

λ1=λ2/2 (ν1= 2*ν2)

Explanation: In order to explain this problem we have to use following  expression for waves.

v=λ*ν ; v is the wave speed. λ and ν are the wavelength and frequency of the wave, respectively.

we have two waves where ν1= 2*ν2 then as the speed is the same for both waves, we have,

λ1*ν1=λ2*ν2  with ν1= 2*ν2 then

λ1=λ2*ν2/v1=λ2*ν2/(2*ν2)= λ2/2

λ1=λ2/2

laticia draws the diagram below to show earth’s magnetic field.

answer

the arrows to the right of earth should point up.

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s