Okay theres three parts. first part asks to

a) calculate the distance she travels along the incline before landing (answer in units of m)

b) determine how long the ski jumper is airborne (answer in units of s)

c) what is the magnitude of the relative angle with which the ski jumper hits the slope? (answer in units of degree)

or im gonna cry tysm

(a)343.50 m

(b)10.82 s

(c)21.23

Explanation:

The x and y cordinates are and respectively

The horizontal distance travelled,

Making t the subject,

Since , we substitute t with the above and obtain

Making d the subject we obtain

d=343.5046

d=343.5m

(b)

Already derived,

hence  

t=10.82 s

(c)

=26m/s

=0-9.8*10.82=-106.04

= -76.23

-76.23+55=-21.23

Therefore angle is

a) , b) , c)

Explanation:

a) The skier is experimenting an parabolic motion. The kinematic expressions for the skier are:

From trigonometry, there is the following relationship between vertical and horizontal components:

The following expression is constructed by substituting and in the vertical motion expression and simplifying the resultant equation:

The roots of the second-order polynomial are:

and

The second one represents the horizontal distance travelled by the skier:

The vertical distance travelled by the skier is:

The distance that skier travels along the incline is computed through the Pythagorean Theorem:

b) The time spent by the skier is:

c) The final vertical velocity of the skier is:

The absolute angle of the velocity is:

The magnitude of the relative angle with which the ski jumper hits the slope is: