Acar of mass 1000.0 kg is traveling along a level road at 100.0 km/h when its brakes are applied. calculate the stopping distance if the coefficient of kinetic friction of the tires is 0.500. neglect air resistance. (hint: since the distance traveled is of interest rather than the time, x is the desired independent variable and not t. use the chain rule to change the variable: .)

Explanation:

It is given that,

Mass of the car, m = 1000 kg

Speed of the car, v = 100 km/h = 27.77 m/s

The coefficient of kinetic friction of the tires,

Let f is the net force acting on the body due to frictional force, such that,

We know that the acceleration of the car in calculus is given by :

, x is the stopping distance

On solving the above equation, we get, x = 78.69 meters

So, the stopping distance for the car is 78.69 meters. Hence, this is the required solution.

cant without the picture! ?