Young david, who slew goliath, experimented with slings before tackling the giant. he found that with a sling of length 0.796 m, he could revolve the sling at the rate of 10.2 rev/s. if he increased the length to 1.14 m, he could revolve the sling only 7.3 rev/s. a) what is the larger of the two linear speeds? answer in units of m/s.

Answer

given,

r₁ = 0.796 m            

ω₁ = 10.2 rev/s            

    = (2π × 10.2) rad/s              

    = 64.088 rad/s              

r₂ = 1.14 m                  

ω₂ = 7.3 rev/s            

    = (2π × 7.3) rad/s

    = 45.87 rad/s

we know,

v = r ω              

v₁ = r₁ ω₁                

v₁ = 0.796 × 64.088

v₁ = 51.014 m/s

v₂ = r₂ ω₂                

v₂ = 1.14 × 45.87  

v₂ = 52.29 m/s

d

explanation:

i think the answer is d. but im not sure!

v=ir = 3x15 =45 v